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drylin® T - system design, lateral, 1 rail and 2 trolleys or 2 rails and 4 trolleys

Step 2:

Check whether the distances between the applied forces are within the permissible values (see maximum permissible distances).

Variant: 1 rail, 2 trolleysVariant: 2 rail, 4 wagons
sy + sz<2 wx - Y0
ay + az<

Step 3:

Step 3
Step 3

A = Coordinate origin
B = Fixed bearing
C = floating bearing

Calculating the required drive force

Firstly, two calculations must be carried out:

01 Step 3
02 Step 3
03 Step 3

The drive force Fa corresponds to the calculated maximum value:

Variables in the calculations

Fa:drive force[N]
Fs:Mass force[N]
Fy, Fz:Bearing load in y or z direction[N]
sx, sy, sz:Distance of the inertial force in x, y or z direction[mm]
ay, az:Distance of the drive force in the y or z direction[mm]
wx:Distance between the wagons on a rail [mm]
LX:Size-dependent constant[mm]
Zm:Size-dependent constant[mm]
Y0:Size-dependent constant[mm]
b:Distance between the guide rails[mm]
µ:coefficient of friction, µ = 0 for static loads, µ = 0.2 for dynamic loads
ZW:Number of slides per rail

Step 4:

Calculate the maximum bearing load

Step 4.1

4.1

Maximum bearing load iny-direction

Step 4.2

4.2

Maximum bearing load inzdirection

Variables in the calculations

Fa:drive force[N]
Fs:Mass force[N]
Fy, Fz:Bearing load in y or z direction[N]
sx, sy, sz:Distance of the inertial force in x, y or z direction[mm]
ay, az:Distance of the drive force in the y or z direction[mm]
wx:Distance between the wagons on a rail [mm]
LX:Size-dependent constant[mm]
Zm:Size-dependent constant[mm]
Y0:Size-dependent constant[mm]
b:Distance between the guide rails[mm]
µ:coefficient of friction, µ = 0 for static loads, µ = 0.2 for dynamic loads
ZW:Number of slides per rail

The constant values

Order numberLX [mm]ZM [mm]Y0 [mm]
TW-01-15291611.5
TW-01-20352315.0
TW-01-25412519.0
TW-01-30492921.5

Coefficients:

1 rail, 2 carriages2 rail, 3-4 wagons
K1|(ay+Y0)/Wx||(ay+Y0)/Wx|
K2(sy+Y0)/Wx(sy+Y0)/Wx
K3|az/Wx||az/Wx|
K4|sx/Wx||sx/Wx|
K5|sz/Wx||sz/Wx|
K6|(sy+Y0)/Zm||(sy+Y0)/b|
K7|sz/Zm||(sz/b)-0.5|

Step 5:

Check the maximum bearing load of the most heavily loaded bearing with the load calculated in step no. 4

Maximum permissible load

Order numberFymax, Fzmax [N]
TW-01-152,000
TW-01-203700
TW-01-255,000
TW-01-307,000

Step 6:

Step 6

graph to determine the maximum permissible speed for the determined bearing load.
X = centric bearing load [N]
Y = permissible average speed [m/s]

Determination of the maximum permissible speed for the load from step no. 4

Consulting

I look forward to answering your questions

Michael Hornung
Michael Hornung+49 2203 9649 0Write e-mail

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